Question 1
Find the acceleration at time t = -1 of a particle whose position at time t is given by
r(t) = 4t
i + t
2 j.
◦
a(-1) = -2
j◦
a(-1) =
i - 2
j◦
a(-1) =
i + 2
j◦
a(-1) = 2
j◦
a(-1) = 2
i +
jQuestion 2
A moving particle starts at an initial position (1, 0, 0) with initial velocity
i - j + k. Its acceleration at time t is
a(t) = 4t
i + 6t
j +
k. Find its velocity and position at time t > 0.
◦
v(t) = (2t
2 + 1)
i + (3t
2 - 1)
j + (t + 1)
k;
r(t) = (t
3 + t + 1)
i + (t
3 - t)
j + (t
2 + t)
k ◦
v(t) = (2t
2 - 1)
i + (3t
2 - 1)
j - (t + 1)
k;
r(t) = (
t
3 + t + 1)
i - (t
3 - t)
j + (
t
2 + t)
k ◦
v(t) = (2t
2 + 1)
i + (3t
2 - 1)
j + (t + 1)
k;
r(t) = (
t
3 + t + 1)
i + (t
3 - t)
j + (
t
2 + t)
k ◦
v(t) = (2t
2 + 1)
i + (3t
2 - 1)
j + (t + 1)
k;
r(t) = (t
3 + t + 1)
i + (t
3 - t)
j - (t
2 + t)
k ◦
v(t) = (2t
2 + 1)
i + (3t
2 + 2)
j + (t + 1)
k;
r(t) = (
t
3 + t + 1)
i + (t
3 + 2t)
j + (
t
2 + t)
k
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