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Author Question: A student prepared a stock solution by dissolving 10.0 g of KOH in enough water to make 150 mL of ... (Read 50 times)

Destiiny22

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on: Jul 8, 2021
A student prepared a stock solution by dissolving 10.0 g of KOH in enough water to make 150 mL of solution. She then took 15.0 mL of the stock solution and diluted it with enough water to make 65.0 mL of a final solution. What is the concentration of KOH for the final solution?
◦ 0.274 mol L-1
◦ 0.356 mol L-1
◦ 2.81 mol L-1
◦ 3.65 mol L-1
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by Destiiny22 on Jul 8, 2021

jliusyl

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Destiiny22

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Reply 2 on: Jul 8, 2021
:D TYSM

cam1229

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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