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Author Question: In a solution prepared by dissolving 0.100 mole of propanoic acid in enough water to make 1.00 L of ... (Read 94 times)

tingc95

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Question 1

If you know Kb for ammonia, NH3, you can calculate the equilibrium constant, Ka, for the following reaction: NH4+ NH3 + H+ by the equation:

Ka = Kw× Kb.
Ka = Kw / Kb.
Ka = 1 / Kb.
Ka = Kb / Kw.
None of these are correct.

Question 2

In a solution prepared by dissolving 0.100 mole of propanoic acid in enough water to make 1.00 L of solution, the pH is observed to be 2.793. The Ka for propanoic acid (HC3H5O2) is:

1.61 × 10–3.
2.60 × 10–5.
1.64 × 10–2.
3.79 × 10–10.
None of these are correct.


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Marked as best answer by tingc95 on Mar 21, 2021

johnharpe

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tingc95

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Reply 2 on: Mar 21, 2021
Excellent


tuate

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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