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Author Question: For the reaction: PCl3(g) + Cl2(g) PCl5(g) at 70.5 C, Kp = 1.05. If one starts with 1.80 atm ... (Read 54 times)

K@

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on: Jul 8, 2021
For the reaction:

PCl3(g) + Cl2(g) PCl5(g) at 70.5 °C, Kp = 1.05.

If one starts with 1.80 atm pressure of PCl3(g), 1.72 atm pressure of Cl2(g), and no PCl5(g), what is the partial pressure of PCl5(g) at equilibrium?
◦ 0.827 atm
◦ 0.856 atm
◦ 0.818 atm
◦ 0.599 atm
◦ 0.080 atm
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by K@ on Jul 8, 2021

sailorcrescent

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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K@

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Reply 2 on: Jul 8, 2021
Gracias!

rleezy04

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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