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Author Question: For the reaction: PCl3(g) + Cl2(g) PCl5(g) at 70.5 C, Kp = 1.05. If one starts with 1.80 atm ... (Read 82 times)

K@

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For the reaction:

PCl3(g) + Cl2(g) PCl5(g) at 70.5 °C, Kp = 1.05.

If one starts with 1.80 atm pressure of PCl3(g), 1.72 atm pressure of Cl2(g), and no PCl5(g), what is the partial pressure of PCl5(g) at equilibrium?
◦ 0.827 atm
◦ 0.856 atm
◦ 0.818 atm
◦ 0.599 atm
◦ 0.080 atm


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Marked as best answer by K@ on Jul 8, 2021

sailorcrescent

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K@

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Reply 2 on: Jul 8, 2021
Thanks for the timely response, appreciate it


strudel15

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Reply 3 on: Yesterday
:D TYSM

 

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