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Author Question: How many millilitres of 0.120 mol L-1 NaOH(aq) are required to titrate 50.0 mL of 0.0998 mol L-1 ... (Read 12 times)

kellyjaisingh

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Question 1

How many millilitres of 0.0850 mol L-1 NaOH(aq) are required to titrate 25.0 mL of (aq) to the equivalence point?
◦ 21.2
◦ 0.245
◦ 3.92
◦ 0.153
◦ 29.5

Question 2

How many millilitres of 0.120 mol L-1 NaOH(aq) are required to titrate 50.0 mL of 0.0998 mol L-1 aqueous butanoic acid to the equivalence point? Butanoic acid is monoprotic. The Ka of butanoic acid is 1.5 × 10-5.
◦ 4.90
◦ 50.0
◦ 41.6
◦ 60.1
◦ 4.65


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Marked as best answer by kellyjaisingh on Jul 8, 2021

okolip

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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kellyjaisingh

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Reply 2 on: Jul 8, 2021
Wow, this really help


mcarey591

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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