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Author Question: A certain species of morning glories produces flowers that are blue, red, or purple. Two ... (Read 26 times)

lak

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A certain species of morning glories produces flowers that are blue, red, or purple. Two pure-breeding purple lines are crossed and produce F1 progeny that all make blue flowers. The F1 are allowed to self and produce 320 F2 progeny with the following distribution: 185 blue, 115 purple, and 20 red.
Which the following is NOT consistent with this information?
◦ Red-flowering plants are homozygous recessive for both genes.
◦ The pure-breeding parental parents are homozygous recessive for mutations in two different genes.
◦ Dominant gene interaction appears to result in a 9:6:1 ratio.
◦ Blue-flowering plants are either A_bb or aaB_.
◦ Analysis of the F1 and F2 progeny phenotypes suggests epistasis.


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Marked as best answer by lak on Jan 12, 2022

jessicaduplan

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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lak

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Reply 2 on: Jan 12, 2022
Wow, this really help


meow1234

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Reply 3 on: Yesterday
Gracias!

 

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