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Author Question: In a goodness-of-fit test, one sample showed that the observed frequency and the expected ... (Read 53 times)

bryantpr01

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on: Feb 26, 2023

Question 1

In a goodness-of-fit test, one sample showed that the observed frequency and the expected frequencyeiwere equal for each cell. The null hypothesis would be:

◦

rejected forα= 0.05, but not rejected forα= 0.025.


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rejected for allα> 0.05.


◦

not rejected at anyαlevel.


◦

rejected at anyαlevel.



Question 2

In a goodness-of-fit test, one sample showed that the observed frequency and the expected frequencyeiwere quite different for each cell. We can conclude that:

◦

the null hypothesis is likely not true.


◦

the null hypothesis is likely true.


◦

the alternative hypothesis is likely true.


◦

the chi-square distribution is likely invalid in this situation.

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Marked as best answer by bryantpr01 on Feb 26, 2023

mllong

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Reply #1 on: Feb 26, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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bryantpr01

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Reply 2 on: Feb 26, 2023
Great answer, keep it coming :)

jojobee318

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Reply 3 on: Yesterday
Wow, this really help

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