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Author Question: In a goodness-of-fit test, one sample showed that the observed frequency and the expected ... (Read 124 times)

bryantpr01

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Question 1

In a goodness-of-fit test, one sample showed that the observed frequency and the expected frequencyeiwere equal for each cell. The null hypothesis would be:

rejected forα= 0.05, but not rejected forα= 0.025.


rejected for allα> 0.05.


not rejected at anyαlevel.


rejected at anyαlevel.



Question 2

In a goodness-of-fit test, one sample showed that the observed frequency and the expected frequencyeiwere quite different for each cell. We can conclude that:

the null hypothesis is likely not true.


the null hypothesis is likely true.


the alternative hypothesis is likely true.


the chi-square distribution is likely invalid in this situation.



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Marked as best answer by bryantpr01 on Feb 26, 2023

mllong

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bryantpr01

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Reply 2 on: Feb 26, 2023
Wow, this really help


6ana001

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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