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Author Question: Calculate the standard enthalpy change for the reaction 2C8H18(l) + 21O2(g) 8CO(g) + 8CO2(g) + ... (Read 62 times)

Lin Shi

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on: Nov 5, 2023
Calculate the standard enthalpy change for the reaction
         2C8H18(l) + 21O2(g) → 8CO(g) + 8CO2(g) + 18H2O(l).
         Given:
         2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l)      ΔH° = –11,020 kJ/mol
         2CO(g) + O2(g) → 2CO2(g)                                 ΔH° = –566.0 kJ/mol
◦ –1.0454 × 104 kJ/mol
◦ –8,756 kJ/mol
◦ –6,492 kJ/mol
◦ 1.0454 × 104 kJ/mol
◦ 1.1586 × 104 kJ/mol
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by Lin Shi on Nov 5, 2023

Mynameisrandom

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Lin Shi

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Reply 2 on: Nov 5, 2023
Great answer, keep it coming :)

Liddy

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Reply 3 on: Yesterday
:D TYSM

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