Author Question: The enthalpy change when a strong acid is neutralized by strong base is 56.1 kJ/mol. If 135 mL of ... (Read 48 times)

knemetz3 · **on:** Nov 5, 2023

Question 1

The combustion of pentane produces heat according to the equation
C₅H₁₂(l) + 8O₂(g) → 5CO₂(g) + 6H₂O(l) ΔH°_rxn= –3,510 kJ/mol
How many grams of CO₂ are produced per 2.50 × 10³ kJ of heat released?
◦ 0.0809 g
◦ 3.56 g
◦ 31.3 g
◦ 157 g
◦ 309 g

Question 2

The enthalpy change when a strong acid is neutralized by strong base is –56.1 kJ/mol. If 135 mL of 0.450 M HI at 23.15°C is mixed with 145 mL of 0.500 M NaOH, also at 23.15°C, what will the maximum temperature reached by the resulting solution? (Assume that there is no heat loss to the container, that the specific heat of the final solution is 4.18 J/g·°C, and that the density of the final solution is that of water.)
◦ 20.24°C
◦ 26.06°C
◦ 29.19°C
◦ 32.35°C
◦ 36.57°C

dsd1212 · **Reply #1 on:** Nov 5, 2023

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