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Author Question: The enthalpy change when a strong acid is neutralized by strong base is 56.1 kJ/mol. If 135 mL of ... (Read 43 times)

knemetz3

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on: Nov 5, 2023

Question 1

The combustion of pentane produces heat according to the equation
         C5H12(l) + 8O2(g) → 5CO2(g) + 6H2O(l)       ΔH°rxn= –3,510 kJ/mol
How many grams of CO2 are produced per 2.50 × 103 kJ of heat released?
◦ 0.0809 g
◦ 3.56 g
◦ 31.3 g
◦ 157 g
◦ 309 g

Question 2

The enthalpy change when a strong acid is neutralized by strong base is –56.1 kJ/mol.  If 135 mL of 0.450 M HI at 23.15°C is mixed with 145 mL of 0.500 M NaOH, also at 23.15°C, what will the maximum temperature reached by the resulting solution? (Assume that there is no heat loss to the container, that the specific heat of the final solution is 4.18 J/g·°C, and that the density of the final solution is that of water.)
◦ 20.24°C
◦ 26.06°C
◦ 29.19°C
◦ 32.35°C
◦ 36.57°C
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by knemetz3 on Nov 5, 2023

dsd1212

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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knemetz3

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Reply 2 on: Nov 5, 2023
Wow, this really help

Liddy

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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