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Author Question: The enthalpy change when a strong acid is neutralized by strong base is 56.1 kJ/mol. If 135 mL of ... (Read 40 times)

knemetz3

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Question 1

The combustion of pentane produces heat according to the equation
         C5H12(l) + 8O2(g) → 5CO2(g) + 6H2O(l)       ΔH°rxn= –3,510 kJ/mol
How many grams of CO2 are produced per 2.50 × 103 kJ of heat released?
◦ 0.0809 g
◦ 3.56 g
◦ 31.3 g
◦ 157 g
◦ 309 g

Question 2

The enthalpy change when a strong acid is neutralized by strong base is –56.1 kJ/mol.  If 135 mL of 0.450 M HI at 23.15°C is mixed with 145 mL of 0.500 M NaOH, also at 23.15°C, what will the maximum temperature reached by the resulting solution? (Assume that there is no heat loss to the container, that the specific heat of the final solution is 4.18 J/g·°C, and that the density of the final solution is that of water.)
◦ 20.24°C
◦ 26.06°C
◦ 29.19°C
◦ 32.35°C
◦ 36.57°C


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Marked as best answer by knemetz3 on Nov 5, 2023

dsd1212

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knemetz3

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Reply 2 on: Nov 5, 2023
Wow, this really help


ashely1112

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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