Use the Born-Haber cycle to calculate the lattice energy of MgO (s) given the following data:
ΔH(sublimation) Mg = 130 kJ/mol
I
1 (Mg) = 738.1 kJ/mol
I
2 (Mg) = 1450 kJ/mol
Bond energy (O=O) = 498.7 kJ/mol
EA (O) = 141 kJ/mol
EA (O
–) = –780 kJ/mol
ΔH
![](data:image/png;base64, iVBORw0KGgoAAAANSUhEUgAAAAsAAAAZCAIAAABo0EPhAAAAV0lEQVR42mP4TwgwDDYVtydYMYCA1YTbWFUA5dO2QRloaqAqtqXBxOFqMc1ggEgg1JLqjkEXYhgOhau4PSENQw5ZxbY07D5FNgMjoGigAuoR1CgbZKEOAGi3+zvC9XwYAAAAAElFTkSuQmCC)
(MgO(s)) = –601.8 kJ/mol
◦ 2200 kJ/mol
◦ 2800 kJ/mol
◦ 3200 kJ/mol
◦ 3800 kJ/mol
◦ 4100 kJ/mol