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Author Question: The sum of squared deviations from the mean divided by the population variance has a(n) ... (Read 41 times)

kwoodring

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on: Jun 24, 2018
The sum of squared deviations from the mean divided by the population variance has a(n) ___________________ _ distribution with ___________________ _ degrees of freedom.
 Fill in the blank(s) with correct word

Question 2

The alternative hypothesis of the Kruskal-Wallis test is that ___________________ _ population locations differ.
 Fill in the blank(s) with correct word


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Andromeda18

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Reply #1 on: Jun 24, 2018
Answer to Question 1

chi-squared; n - 1
chi-squared; n-1

Answer to Question 2

at least two
at least 2
two or more
2 or more


kwoodring

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Reply 2 on: Jun 24, 2018
Great answer, keep it coming :)

steff9894

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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