Consider the following information. SSTR = 6750 H0: 1 = 2 = 3 = 4 ...

[BrownTown3]

Consider the following information. SSTR = 6750 H0: 1 = 2 = 3 = 4 SSE = 8000 Ha: At least one mean is different The null hypothesis is to be tested at the 5 level of significance. The null hypothesis
 a. should be rejected.
  b. should not be rejected.
  c. was designed incorrectly.
  d. cannot be tested.

Question 2

If customer 2 has a service time of 1.6, and if customer 3 has an interarrival time of 1.1 and a service time of 2.3, when will customer 3's service be completed?
 a. 5.0
  b. 3.9
  c. 3.4
  d. There is not enough information to answer.

[yasmina]

Answer to Question 1

a

Answer to Question 2

d