Author Question: In a two-factor ANOVA, the total sum of squares can be partitioned into four parts; the variation ... (Read 119 times)

craiczarry

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In a two-factor ANOVA, the total sum of squares can be partitioned into four parts; the variation due to factor A, the variation due to factor B, the variation due to blocking, and the error variation.
 
  Indicate whether the statement is true or false

Question 2

The number of defects discovered in a random sample of 100 products produced at the Berdan Manufacturing Company is binomially distributed with p = .03. Based on this, the standard deviation of the number of defects per sample of size 100 is 2.91.
 
  Indicate whether the statement is true or false



Jmfn03

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Answer to Question 1

FALSE

Answer to Question 2

FALSE



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