For a given data set, the lower quartile is 45, the median is 50, ...

[MirandaLo]

For a given data set, the lower quartile is 45, the median is 50, and the upper quartile is
  57. The minimum value in the data set is 32, and the maximum is 81.
 
  a. Find the interquartile range.
  b. Find the inner fences.
  c. Find the outer fences.
  d. Is either of the minimum or maximum values considered an outlier? Explain.

Question 2

The amount of television viewed by today's youth is of primary concern to Parents
  Against Watching Television (PAWT).
 
  Three hundred parents of elementary school-aged
  children were asked to estimate the number of hours per week that their child watches
  television. The upper quartile for the distribution was given as 20 hours. Interpret this
  value.

[olderstudent]

Answer to Question 1

a. The interquartile range is 57 - 45 = 12.
b. The inner fences are 45 - 1.5(

Answer to Question 2

75 of the TV viewing times are less than 20 hours per week. 25 of the times exceed 20 hours per week.

[MirandaLo]

Thanks for the timely response, appreciate it

[lkanara2]

Gracias!