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Author Question: Steve's average golf score at his local course is 92.9 from a random sample of 60 rounds of golf. ... (Read 449 times)

Pineappleeh

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on: Jun 24, 2018
Steve's average golf score at his local course is 92.9 from a random sample of 60 rounds of golf. Assume that the population standard deviation for his golf score is 4.2. The 99 confidence interval around this sample mean is ________.
 
  A) (87.6, 98.2)
  B) (90.7, 95.1)
  C) (89.5, 96.3)
  D) (92.4, 94.2)

Question 2

Suppose the average driving distance for last year's Masters Golf Tournament was 282.5 yards with a standard deviation of 12.2 yards. A random sample of 30 drives was selected from a total of 4,144 drives that were hit during this tournament.
 
  What is the probability that the sample average was 279 yards or less?A) 0.3540
  B) 0.2676
  C) 0.1611
  D) 0.0582
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dellikani2015

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Reply #1 on: Jun 24, 2018
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Pineappleeh

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Reply #2 on: Jun 24, 2018
Thank you :)


dellikani2015

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Reply #3 on: Jun 24, 2018
Happy to help you


Miss CML

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Reply #4 on: Jul 29, 2022
Thank you


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