A voltage difference of 18.7 mV is measured when a blood sample ...

[Beheh]

A voltage difference of 18.7 mV is measured when a blood sample is being analyzed for pH. What is the resultant pH of the blood?
 
  a. 7.54 c. 7.14
  b. 7.34 d. 8.71

Question 2

A blood sample is analyzed within a Sanz electrode. The voltage difference = 44.90 mV. What is the resultant pH of this blood?
 
  a. 7.11 c. 7.57
  b. 7.34 d. 8.18

[s.meritte]

Answer to Question 1

ANS: C
A voltage of 61.5 mV is developed for every pH unit difference between the sample and the measuring electrode, which remains 6.84. Therefore, the voltage difference is 18.7 mV divided by 61.5 mV, or 0.30. The resultant pH can be calculated as 6.84 + 0.30 = 7.14.

Answer to Question 2

ANS: C
A voltage of 61.5 mV is developed for every pH unit difference between the sample and the measuring electrode, which remains 6.84. Therefore, the voltage difference is 44.90 mV divided by 61.5 mV, or 0.73. The resultant pH can be calculated as 6.84 + 0.73 = 7.57.

[Beheh]

TYSM

[amandanbreshears]

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