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Author Question: Assume that x is normally distributed random variable with a mean of 30 and a standard deviation of ... (Read 76 times)

go.lag

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on: Jul 24, 2018
Assume that x is normally distributed random variable with a mean of 30 and a standard deviation of 6 . Find P(21 < x < 37).

Question 2

Assume that x is normally distributed random variable with a mean of 30 and a standard deviation of 6 . Find P(32< x < 47).


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elizabethrperez

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Reply #1 on: Jul 24, 2018
Answer to Question 1

P(21 < x < 37) = P(-1.50 < z < 1.17) = 0.4332 + 0.3790 = 0.8122

Answer to Question 2

P(32< x < 47) = P(0.33 < z < 2.83 ) = 0.4977  0.1293 = 0.3684


go.lag

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Reply #2 on: Jul 24, 2018
Thanks


elizabethrperez

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Reply #3 on: Jul 24, 2018
Welcome :)


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