The formula for the chi-squared statistic is A) (OE)2/E B) ...

[mydiamond]

The formula for the chi-squared statistic is
 
  A) (OE)2/E
  B) (OE)2/E
  C) O/(OE)2
  D) E/(OE)2

Question 2

Using a normal curve table, if a person has a score of 4.78 on a test, which equals a Z score of 1.5, the percentage of cases that lie above this score is
 
  A) 43.32  50 = 6.68
  B) 50  43.32 = 6.68
  C) 100  43.32 = 56.68
  D) 50 + 43.32 = 93.32

[macagn]

Answer to Question 1

A

Answer to Question 2

B

[mydiamond]

Excellent

[chjcharjto14]

Thanks for the timely response, appreciate it