A student wished to use a table of areas for the standard normal ...

[Haya94]

A student wished to use a table of areas for the standard normal curve to find the z-score having an area to its right of 0.52. The student started by looking for the closest area to 0.
 
  52 in the body of the table and reading off the corresponding z-score which was 0.05. She then subtracted this z-score from 1 to get 0.95. Was her reasoning correct? If not, where did she go wrong and how would you have solved the problem?

Question 2

256 people were asked if they were satisfied with their jobs. 45 said that they were. H0: p = 0.36.
 
  A) 4.125 B) 0.188 C) 2.612 D) 3.000

[ms_sulzle]

Answer to Question 1

Answers will vary. Possible answer: The student's reasoning was not correct. The original area should be subtracted from 1 to find the area to the left of the z-score, which is 0.48. The student should then look for the closest area to 0.48 in the body of the table and read off the corresponding z-score, which is -0.05.

Answer to Question 2

D

[Haya94]

Excellent

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