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Author Question: Determine the power from the visible, UV, and IR components of sunlight striking the surface of a PV ... (Read 71 times)

Lobcity

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on: Jul 26, 2018
Determine the power from the visible, UV, and IR components of sunlight striking the surface of a PV panel with a total irradiance of 500 W/m2 if the panel is 0.5 m square. What is the energy in kWh if the specified irradiance is on the panel for 10 hours?
 
  What will be an ideal response?

Question 2

Determine the fill factor for a PV cell with IOC = 3 A and VOC =0.55 V if the power at the maximum power point is 1.75 W.
 
  What will be an ideal response?


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bfulkerson77

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Reply #1 on: Jul 26, 2018
Answer to Question 1

Incident P = (500 W/m2)(0.5 m2) 250 W

Incident W = Pt = (250 W)(10 h) = 2500 Wh = 2.5 kWh

Answer to Question 2

FF = (VMPP)(IMPP) / (VOC)(ISC) = PMPP / (VOC)(IOC) = 1.75 W / (0.55 V)(3 A) = 1.06


Lobcity

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Reply 2 on: Jul 26, 2018
Wow, this really help

TheNamesImani

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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