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Author Question: A 0.30 kg mass is suspended on a string. In equilibrium the mass stretches the spring 2.0 cm ... (Read 72 times)

mspears3

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on: Jul 27, 2018
A 0.30 kg mass is suspended on a string. In equilibrium the mass stretches the spring 2.0 cm downward. The mass is then pulled an additional distance of 1.0 cm down and released from rest.
 
  (a) Write down its equation of motion.
  (b) Calculate the velocity of the mass at T/3 s.

Question 2

The net direction in which electrons flow through a circuit is:
 
  A) the direction of the conventional current.
  B) opposite of the direction of the conventional current.


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cdmart10

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Reply #1 on: Jul 27, 2018
Answer to Question 1

(a) y = -0.01 cos(22.1 t) meters
(b) 0.19 m/s

Answer to Question 2

B


mspears3

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Reply #2 on: Jul 27, 2018
Thanks


cdmart10

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Reply #3 on: Jul 27, 2018
Welcome :)


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