Author Question: The ionization energy for the hydrogen atom is 13.6 eV. What is the energy of a photon that is ... (Read 53 times)

mwit1967 · **on:** Jul 28, 2018

The ionization energy for the hydrogen atom is 13.6 eV. What is the energy of a photon that is emitted as a hydrogen atom makes a transition between the n = 4 and n = 3 states?
a. 3.40 eV
c. 6.80 eV
b. 0.66 eV
d. 2.55 eV

Question 2

The Lyman series of hydrogen is made up of those transitions made from higher levels to n = 1 . If the first line (n = 2 to n = 1) in this series has a wavelength of 122 nm, what is the wavelength of the third line (n = 4 to n = 1)?
a. 364 nm
c. 103 nm
b. 97.6 nm
d. 486 nm