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Author Question: A 0.120-pF parallel-plate capacitor is charged to a potential difference of 10.0 V and then ... (Read 142 times)

Chloeellawright

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A 0.120-pF parallel-plate capacitor is charged to a potential difference of 10.0 V and then disconnected from the battery. A cosmic ray burst creates 1.00  106 electrons and 1.00  106 positive charges between the plates. If the charges do not recombine, but reach the oppositely charged plates, by how much is the potential difference between the capacitor plates reduced?
 a. 1.33 V
  b. 7.34 V
  c. 8.67 V
  d. 1,330 V
  e. 8,670 V

Question 2

An initially uncharged parallel plate capacitor of capacitance C is charged to potential V by a battery. The battery is then disconnected. Which statement is correct?
 a. There is no charge on either plate of the capacitor.
  b. The capacitor can be discharged by grounding any one of its two plates.
  c. Charge is distributed evenly over both the inner and outer surfaces of the plates.
  d. The magnitude of the electric field outside the space between the plates is approximately zero.
  e. The capacitance increases when the distance between the plates increases.



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stillxalice

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Answer to Question 1

a

Answer to Question 2

d





 

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