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Author Question: A fireman is sliding down a fire pole. As he speeds up, he tightens his grip on the pole, thus ... (Read 14 times)

vicky

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on: Jul 29, 2018
A fireman is sliding down a fire pole. As he speeds up, he tightens his grip on the pole, thus increasing the vertical frictional force that the pole exerts on the fireman. When the force on his hands equals his weight, what happens to the fireman?
 
  A) The fireman comes to a stop.
  B) The fireman descends with slower and slower speed.
  C) The fireman descends with a smaller but non-zero acceleration.
  D) The fireman continues to descend, but with constant speed.
  E) The acceleration of the fireman is now upward.

Question 2

The length and width of a rectangle are 1.125 m and 0.606 m, respectively. You calculate the rectangle's perimeter by adding these numbers and multiplying by two. Your calculator's display reads 3.462.
 
  To the correct number of significant figures, the perimeter should be written as A) 3.5 m.
  B) 3.46 m.
  C) 3.462 m.
  D) 3.4620 m.
Physics ¦ Walker ¦ 5th Edition
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Anton

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Reply #1 on: Jul 29, 2018
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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vicky

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Reply 2 on: Jul 29, 2018
:D TYSM

alvinum

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Reply 3 on: Yesterday
Gracias!

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