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Author Question: An oxygen molecule falls in a vacuum. From what height must it fall so that its kinetic energy at ... (Read 15 times)

magmichele12

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on: Jul 29, 2018
An oxygen molecule falls in a vacuum. From what height must it fall so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 920 K?
 
  A) 36,500 meters
  B) 12,100 meters
  C) 24,300 meters
  D) 48,700 meters

Question 2

The electric field 1.5 cm from a very small charged object points toward the object with a magnitude of 180,000 N/C.
 
  What is the charge on the object? (k = 1/40 = 8.99  109 N  m2/C2)
  A) -4.5 nC
  B) +4.5 nC
  C) -5.0 nC
  D) +5.0 nC


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JaynaD87

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Reply #1 on: Jul 29, 2018
Answer to Question 1

A

Answer to Question 2

A


magmichele12

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Reply 2 on: Jul 29, 2018
Excellent

billybob123

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Reply 3 on: Yesterday
Gracias!

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