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Author Question: An oxygen molecule falls in a vacuum. From what height must it fall so that its kinetic energy at ... (Read 33 times)

magmichele12

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An oxygen molecule falls in a vacuum. From what height must it fall so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 920 K?
 
  A) 36,500 meters
  B) 12,100 meters
  C) 24,300 meters
  D) 48,700 meters

Question 2

The electric field 1.5 cm from a very small charged object points toward the object with a magnitude of 180,000 N/C.
 
  What is the charge on the object? (k = 1/40 = 8.99  109 N  m2/C2)
  A) -4.5 nC
  B) +4.5 nC
  C) -5.0 nC
  D) +5.0 nC



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JaynaD87

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Answer to Question 1

A

Answer to Question 2

A




magmichele12

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Reply 2 on: Jul 29, 2018
Great answer, keep it coming :)


pangili4

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Reply 3 on: Yesterday
Gracias!

 

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