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Author Question: A random sample of 89 tourists in the Grand Bahamas showed that they spent an average of 2,860 (in a ... (Read 183 times)

erika

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on: Aug 1, 2018
A random sample of 89 tourists in the Grand Bahamas showed that they spent an average of 2,860 (in a week) with a standard deviation of 126, and a sample of 64 tourists in New Province showed that they spent an average of 2,935 (in a week) with a standard deviation of 138 . We are interested in determining if there is any significant difference between the average expenditures of those who visited the two islands.
 a. Determine the degrees of freedom for this test.
  b. Compute the test statistic.
  c. Compute the p-value.
  d. What is your conclusion? Let  = .05.

Question 2

A random sample of 150 Chattanooga residents was surveyed and 60 indicated that they participated in a recycling program. In Knoxville, a random sample of 120 residents was surveyed and 36 claimed to recycle.
 a. Determine a 95 confidence interval estimate for the difference between the proportions of residents recycling in the two cities.
 b. From your answer in part (a), is there sufficient evidence to conclude that there is a significant difference in the proportion of residents participating in a recycling program?


leahm14

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Reply #1 on: Aug 1, 2018
Answer to Question 1

a . 128
b. Test statistic t = 3.438
c. p-value (two-tailed) < 0.005 (almost 0)
d. p-value < .05; reject H0, there is a significant difference

Answer to Question 2

a . .0134 to .2134 (Chattanooga  Knoxville)
b. No, because the interval for the proportions ranges from a negative value to a positive value.


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erika

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Reply #2 on: Aug 1, 2018
TY


leahm14

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Reply #3 on: Aug 1, 2018
You're welcome


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