Following is a chair conformation of cyclohexane with the carbon ...

[wrbasek0]

Following is a chair conformation of cyclohexane with the carbon atoms numbered 1 through 6.
 
 

(a) Draw hydrogen atoms that are above the plane of the ring on carbons 1 and 2 and below the plane of the ring on carbon
  4.
  (b) Which of these hydrogens are equatorial? Which are axial?
  (c) Draw the alternative chair conformation. Which hydrogens are equatorial? Which are axial? Which are above the plane
  of the ring? Which are below it?

Question 2

Write molecular formulas for each bicycloalkane, given its number of carbon atoms.
  (a) Hydrindane (9 carbons)
  (b) Decalin (10 carbons)
 

(c) Norbornane (7 carbons)
   

Question 3

Write the molecular formula, IUPAC name, and common name for each cycloalkane.
 
 
 

Question 4

Combine the proper prefix, infix, and suffix and write the IUPAC name for each compound.

Question 5

Draw line-angle formulas for the three constitutional isomers with the molecular formula C5H12.

Question 6

Do the line-angle formulas in each pair represent the same compound or constitutional isomers.
 
 

Question 7

Describe the bonding in PCl₅ without using d orbitals. As a hint, the geometry of PCl₅ is as shown:

Question 8

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Based on the bond angles

Question 9

Why are the following molecular formulas impossible?
  (a) CH_{5
  (b) C2H7}

[billybob123]

Answer to Question 1


In the above figure (a) = axial and (e) = equatorial.

Answer to Question 2

(a) Hydrindane (9 carbons)

Hydrindane
Molecular Formula C9H16

(b) Decalin (10 carbons)

Decalin
Molecular Formula C10H18

(c) Norbornane (7 carbons)

Norbornane
Molecular Formula C7H12

Answer to Question 3

(a) Molecular Formula C9 H1 8
(2-Methylpropyl)cyclopentane (IUPAC)
Isobutylcyclopentan e (Common)

(b)

Molecular Formula C1 1H2 2
(1-Methylpropyl)cycloheptane (IUPAC)
sec-Butylcycloheptane (Common)

(c)

Molecular Formula C6 H1 2
1-Ethyl-1-methylcyclopropane (IUPAC and Common)

Answer to Question 4



Answer to Question 5



Answer to Question 6

(a) These molecules are constitutional isomers. Each has six carbons in the longest chain. The first has one-carbon
branches on carbons 3 and 4 of the chain; the second has one-carbon branches on carbons 2 and 4 of the chain.

(b) These molecules are identical. Each has five carbons in the longest chain, and one-carbon branches on carbons
2 and 3 of the chain.

Answer to Question 7

[wrbasek0]

Gracias!

[AngeliqueG]

TYSM