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Author Question: How many grams of CaCl2 are formed when 15.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas? 2 ... (Read 1778 times)

Hungry!

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on: Aug 27, 2018
How many grams of CaCl2 are formed when 15.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas? 2 Ca(OH)2(aq) + 2 Cl2(g)  Ca(OCl)2(aq) + CaCl2(aq) + 2 H2O(l)
 
  A) 0.00197 g
  B) 0.00394 g
  C) 0.00789 g
  D) 0.0507 g

Question 2

The correct name for Co(NH3)5ClCl2 is ________.
 
  A) pentaaminechlorocob alt (III) chloride
  B) chloropentaammoniac obalt (II) chloride
  C) pentaammoniachloroc obalt (II) chloride
  D) cobalt (III) pentaamino trichloride
  E) cobalt (III) pentaamminemonochlo ride chloride


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tsternbergh47

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Reply #1 on: Aug 27, 2018
Answer to Question 1

A

Answer to Question 2

A


Hungry!

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Reply #2 on: Aug 27, 2018
Thank you!


tsternbergh47

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Reply #3 on: Aug 27, 2018
Always glad to help...


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