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Author Question: How many moles of CO2 are produced when 2.5 moles of O2 react according to the following equation? ... (Read 40 times)

tingc95

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How many moles of CO2 are produced when 2.5 moles of O2 react according to the following equation?
 
  C3H5 + 5 O2  3 CO2 + 4 H2O
 
  A) 1.5
  B) 3
  C) 5
  D) 6
  E) 18

Question 2

Interpret in words the equation:
 
  P4O10 (s) + 6 H2O (l)  4 H3PO4 (aq)
 
  A) One mole of solid tetraphosphorus decaoxide reacts with six moles of liquid water to produce four moles of phosphoric acid solution.
  B) Zero moles of solid phosphoric oxide dissolve in six moles of water to produce four moles of phosphorous acid.
  C) One mole of phosphorus(X) oxide combines with six moles of water to produce four moles of solution of hydrogen phosphate.
  D) Four moles of solid phosphorus, five moles of diatomic oxygen gas, and six moles of liquid water react together to produce four moles of phosphoric acid in solution.
  E) Four atoms of phosphorus, 16 atoms of oxygen, and 12 atoms of hydrogen rearrange to produce four molecules of phosphoric acid.

Question 3

Determine the number of moles of water produced when one mole of NH3 reacts according to the balanced reaction shown.
 
  4 NH3 + 5 O2  4 NO + 6 H2O
 
  A) 1.00
  B) 1.25
  C) 1.50
  D) 0.67
  E) 1.33

Question 4

In the reaction shown, how many moles of HCl are needed to react with 2.4 moles of Al?
 
  2 Al + 6 HCl  2 AlCl3 + 3 H2
 
  A) 0.8
  B) 1.3
  C) 4.8
  D) 6.4
  E) 7.2

Question 5

In the balanced reaction shown, the mole ratio of Fe2S3 to O2 is
 
  Fe2S3 + 4 O2  2 FeO + 3 SO2
 
  A) 5 to 5.
  B) 1 to 4.
  C) 4 to 1.
  D) 1 to 2.
  E) 4 to 3.

Question 6

The number of grams in 7.00 moles of N2 is ________.
 
  A) 7  (6.02  1023)
  B) 14.0
  C) 28.0
  D) 98.0
  E) 196



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Ddddd

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Answer to Question 1

A

Answer to Question 2

A

Answer to Question 3

C

Answer to Question 4

E

Answer to Question 5

B

Answer to Question 6

E




tingc95

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  • Posts: 556
Reply 2 on: Aug 27, 2018
Thanks for the timely response, appreciate it


carlsona147

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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