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Author Question: How many g of Fe(NO3)3 are present in a 20.0 mL sample of a 0.500 M solution? A) 2.14 g B) 9.68 ... (Read 188 times)

jerry coleman

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on: Aug 27, 2018
How many g of Fe(NO3)3 are present in a 20.0 mL sample of a 0.500 M solution?
 
  A) 2.14 g
  B) 9.68 g
  C) 4.84 g
  D) 2.42 g
  E) 1.21 g

Question 2

How much energy is evolved during the formation of 98.7 g of Fe, according to the reaction below?
 
  Fe2O3(s) + 2 Al(s)  Al2O3(s) + 2 Fe(s) Hrxn = -852 kJ
 
  A) 753 kJ
  B) 1.51  103 kJ
  C) 4.20  103 kJ
  D) 482 kJ
  E) 241 kJ

Question 3

Carbon dioxide obeys the octet rule.
 
  Indicate whether the statement is true or false


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al

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Reply #1 on: Aug 27, 2018
Answer to Question 1

D

Answer to Question 2

A

Answer to Question 3

TRUE


jerry coleman

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Reply 2 on: Aug 27, 2018
Wow, this really help

bimper21

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Reply 3 on: Yesterday
Gracias!

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