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Author Question: Heat is added to a 3.0 kg piece of ice at a rate of How long will it take for the ice at 0.0 C to ... (Read 287 times)

viki

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on: Oct 11, 2019

Question 1

A 2294-kg sample of water at 0° C is cooled to and freezes in the process. How much heat is liberated? For water LF = 334,000 J/kg and LV = 2.256 × 106 J/kg. The specific heat of ice is 2050 J/kg ∙ K.
◦ 1,110,000 kJ
◦ 334,000 kJ
◦ 597,000 kJ
◦ 935,000 kJ

Question 2

Heat is added to a 3.0 kg piece of ice at a rate of How long will it take for the ice at 0.0° C to melt? For water LF = 334,000 J/kg and LV = 2.246 × 106 J/kg.
◦ 640,000 s
◦ 1000 s
◦ 0.0 s
◦ 1.6 s
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Marked as best answer by viki on Oct 11, 2019

af

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Reply #1 on: Oct 11, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Payton Breedlove

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Reply #2 on: Apr 30, 2020
Thank You!


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