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Author Question: The temperature of an ideal gas in a sealed rigid 0.60-m3 container is reduced from 460 K to The ... (Read 109 times)

swpotter12

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on: Oct 11, 2019

Question 1

A rigid container is filled with 4.0 mol of air with CV = 2.5R. How much does the internal (thermal) energy of the air change if its temperature rises from to (R = 8.31 J/mol ∙ K)
◦ 8940 J
◦ 430 J
◦ 3580 J
◦ 35,800 J

Question 2

The temperature of an ideal gas in a sealed rigid 0.60-m3 container is reduced from 460 K to The final pressure of the gas is The molar heat capacity at constant volume of the gas is 28.0 J/mol ∙ K. How much heat is absorbed by the gas during this process? (R = 8.31 J/mol ∙ K)
◦ -130 kJ
◦ 170 kJ
◦ -170 kJ
◦ 0 kJ
◦ 130 kJ
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Marked as best answer by swpotter12 on Oct 11, 2019

Gabe

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Reply #1 on: Oct 11, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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swpotter12

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Reply 2 on: Oct 11, 2019
Wow, this really help

Perkypinki

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Reply 3 on: Yesterday
Excellent

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