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Author Question: A light ray in glass arrives at the glass-water interface an an angle of = 48 with the normal. The ... (Read 166 times)

storky111

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on: Oct 11, 2019

Question 1

A convex mirror has a focal length of magnitude f. An object is placed in front of this mirror at a point f  from the face of the mirror. The image will appear
◦ inverted and enlarged.
◦ upright and reduced.
◦ upright and enlarged.
◦ inverted and reduced.
◦ behind the mirror.

Question 2

A light ray in glass arrives at the glass-water interface an an angle of θ = 48° with the normal. The refracted ray in water makes an angle φ = 72° angle with the normal, as shown in the figure.The index of refraction of water is 1.33. The angle of incidence is now changed to θ = 37°. What is the new angle of refraction φ in the water?
 

◦ 46°
◦ 54°
◦ 52°
◦ 48°
◦ 50°
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Marked as best answer by storky111 on Oct 11, 2019

jxjsniuniu

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Reply #1 on: Oct 11, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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storky111

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Reply #2 on: Oct 11, 2019
Excellent


jxjsniuniu

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Reply #3 on: Oct 11, 2019
Great! Please up vote :D


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