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Author Question: As shown in the figure, a laser positioned on a ship is used to communicate with a small research ... (Read 136 times)

tichca

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Question 1

A light ray in glass arrives at the glass-water interface at an angle of θ = 48° with the normal. The refracted ray in water makes an angle θ = 61° with the normal, as shown in the figure. The index of refraction of water is 1.33. The angle of incidence is now changed to θ = 25°. What is the new angle of refraction φ in the water?


◦ 54°
◦ 62°
◦ 60°
◦ 56°
◦ 30°

Question 2

As shown in the figure, a laser positioned on a ship is used to communicate with a small research submarine resting on the bottom of a lake. The laser is positioned 12 m above the surface of the water, and it strikes the water 20 m from the side of the ship. The water is 58 m deep and has an index of refraction of 1.33. How far horizontally is the submarine from the side of the ship? (Assume all numbers are accurate to three significant figures.)


◦ 89 m
◦ 69 m
◦ 49 m
◦ 79 m
◦ 59 m


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Marked as best answer by tichca on Oct 11, 2019

meltdown117

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tichca

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Reply 2 on: Oct 11, 2019
Wow, this really help


TheDev123

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Reply 3 on: Yesterday
Gracias!

 

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