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Author Question: An astronaut on a spaceship moving at 0.927c says that the trip between two stationary stars took ... (Read 577 times)

rosent76

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on: Oct 11, 2019

Question 1

As measured in Earth's rest frame, a spaceship traveling at 0.9640c takes to travel between two planets that are not moving relative to each other. How long does the trip take as measured by someone on the spaceship?
◦ 2.79 y
◦ 6.83 y
◦ 28.8 y
◦ 39.5 y

Question 2

An astronaut on a spaceship moving at 0.927c says that the trip between two stationary stars took How long does this journey appear to take to someone in the rest frame of the two stars?
◦ 2.30 y
◦ 1.60 y
◦ 11.4 y
◦ 12.6 y
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Marked as best answer by rosent76 on Oct 11, 2019

InfiniteSteez

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Reply #1 on: Oct 11, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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rosent76

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Reply 2 on: Oct 11, 2019
Excellent

Liamb2179

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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