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Author Question: P(x) = -x3 + x2 - 60x + 100, x 5 is an approximation to the total profit (in thousands of dollars) ... (Read 136 times)

mrsjacobs44

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on: Oct 21, 2019
P(x) = -x3 + x2 - 60x + 100, x ≥ 5 is an approximation to the total profit (in thousands of dollars) from the sale of x hundred thousand tires. Find the number of hundred thousands of tires that must be sold to maximize profit.
◦ 4.5 hundred thousand
◦ 5.5 hundred thousand
◦ 5 hundred thousand
◦ 4 hundred thousand
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Marked as best answer by mrsjacobs44 on Oct 21, 2019

Jane

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Reply #1 on: Oct 21, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Shelles

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Reply #2 on: Oct 21, 2019
P(x) = -x3 + 12x2 - 36x + 400, x ≥ 3 is an approximation to the total profit (in thousands of dollars) from the sale of x hundred thousand tires. Find the number of hundred thousands of tires that must be sold to maximize profit.
◦ 7 hundred thousand
◦ 6 hundred thousand
◦ 2 hundred thousand
◦ 3 hundred thousand


jazzlynnnnn

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Reply #3 on: Oct 21, 2019
6 hundred thousand


Shelles

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Reply #4 on: Oct 21, 2019
Excellent


jazzlynnnnn

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Reply #5 on: Oct 21, 2019
Great! Please up vote :D


Melani1276

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Reply #6 on: Oct 21, 2019
P(x) = -x3 + 24x2 - 144x + 50, x ≥ 2 is an approximation to the total profit (in thousands of dollars) from the sale of x hundred thousand tires. Find the number of hundred thousands of tires that must be sold to maximize profit.
◦ 10 hundred thousand
◦ 2 hundred thousand
◦ 12 hundred thousand
◦ 4 hundred thousand


onowka

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Reply #7 on: Oct 21, 2019
12 hundred thousand


torybrooks

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Reply #8 on: Oct 21, 2019
P(x) = -x3 + 12x2 - 21x + 100, x ≥ 4 is an approximation to the total profit (in thousands of dollars) from the sale of x hundred thousand tires. Find the number of hundred thousands of tires that must be sold to maximize profit.
◦ 10 hundred thousand
◦ 7 hundred thousand
◦ 4 hundred thousand
◦ 13 hundred thousand


efwsefaw

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Reply #9 on: Oct 21, 2019
7 hundred thousand


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