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Author Question: If 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of metal ... (Read 1230 times)

laurencescou

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on: Nov 18, 2019

Question 1

If 8.32 g of copper is mixed with 5.2372 × 10-2 mol of zinc to create the alloy brass, how many metal atoms total are present in the brass?
◦ 1.10 × 1023 metal atoms
◦ 7.88 × 1022 metal atoms
◦ 3.04 × 10-25 metal atoms
◦ 3.15 × 1022 metal atoms
◦ 3.15 × 10-22 metal atoms

Question 2

If 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of metal are present in the pewter?
◦ 0.6233 mol total
◦ 1.037 mol total
◦ 1.604 mol total
◦ 0.8675 mol total
◦ 0.9643 mol total
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Marked as best answer by laurencescou on Nov 18, 2019

blazinlyss

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ghassan2271

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Reply #2 on: Feb 14, 2022
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