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Author Question: According to the following reaction, how many moles of Fe(OH)2 can form from 175.0 mL of 0.227 mol ... (Read 102 times)

jessicacav

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on: Nov 18, 2019

Question 1

How many ions are present in 30.0 mL of a 0.600 mol L-1 Na2CO3 solution?
◦ 3.25 × 1022 ions
◦ 1.08 × 1022 ions
◦ 3.61 × 1021 ions
◦ 5.42 × 1022 ions
◦ 2.17 × 1022 ions

Question 2

According to the following reaction, how many moles of Fe(OH)2 can form from 175.0 mL of 0.227 mol L-1 LiOH solution? Assume that there is excess FeCl2.

FeCl2(aq) + 2LiOH(aq) → Fe(OH)2(s) + 2LiCl(aq)

◦ 5.03 × 10-2 moles
◦ 2.52 × 10-2 moles
◦ 6.49 × 10-2 moles
◦ 1.99 × 10-2 moles
◦ 3.97 × 10-2 moles
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by jessicacav on Nov 18, 2019

Joc

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jessicacav

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Reply 2 on: Nov 18, 2019
Great answer, keep it coming :)

steff9894

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Reply 3 on: Yesterday
Wow, this really help

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