In the presence of excess oxygen, methane gas burns in a constant ...

[jenna1]

Question 1

When 1.50 mol of CH4(g) reacts with excess Cl2(g) at constant pressure according to the chemical equation shown below, 1062 kJ of heat are released. Calculate the value of ΔH for this reaction, as written.

2CH4(g) + 3Cl2(g) → 2CHCl3(l) + 3H2(g)

Δ rH° = ?

◦ +1420 kJ mol^-1
◦ -708 kJ mol^-1
◦ +708 kJ mol^-1
◦ -1420 kJ mol^-1

Question 2

In the presence of excess oxygen, methane gas burns in a constant pressure system to yield carbon dioxide and water:

CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l)

Δ rH = -890.0 kJ

Calculate the value of q (kJ) in this exothermic reaction when 1.90 g of methane is combusted at constant pressure.
◦ 29.3 kJ mol^-1
◦ -1.06 × 10^-5 kJ mol^-1
◦ 0.0342 kJ mol^-1
◦ -106 kJ mol^-1
◦ -0.00946 kJ mol^-1

[amandanbreshears]

A FREE account is required to view all solutions! Click to Register

Login with Facebook Login with Google Login with Email

Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.

Answer Preview

Only 56% of students answer this correctly

[jenna1]

Thanks for the timely response, appreciate it

[scottmt]

TYSM