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Author Question: How many grams of KBr are required to make 350. mL of a 0.115 mol L-1 KBr solution? (Read 273 times)

jlmhmf

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on: Nov 18, 2019

Question 1

To make a 0.500 mol L-1 solution, one could take 0.500 moles of solute and add
◦ enough solvent to make 1.00 L of solution.
◦ 1.00 L of solvent.
◦ enough solvent to make 1.00 kg of solution.
◦ 1.00 kg of solvent.

Question 2

How many grams of KBr are required to make 350. mL of a 0.115 mol L-1 KBr solution?
◦ 40.3 g
◦ 3.04 g
◦ 4.79 g
◦ 0.338 g
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Marked as best answer by jlmhmf on Nov 18, 2019

alexanderhamilton

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jlmhmf

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Reply 2 on: Nov 18, 2019
Gracias!

ryansturges

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Reply 3 on: Yesterday
Wow, this really help

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