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Author Question: To make a 2.00 mol kg-1 solution, one could take 2.00 moles of solute and add (Read 115 times)

mspears3

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on: Nov 18, 2019

Question 1

What is the molality of a glucose solution prepared by dissolving 18.0 g of glucose, C6H12O6, in 125.9 g of water?
◦ 7.94 × 10-4 mol kg-1
◦ 0.695 mol kg-1
◦ 0.143 mol kg-1
◦ 0.794 mol kg-1

Question 2

To make a 2.00 mol kg-1 solution, one could take 2.00 moles of solute and add
◦ enough solvent to make 1.00 L of solution.
◦ enough solvent to make 1.00 kg of solution.
◦ 1.00 kg of solvent.
◦ 1.00 L of solvent.
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by mspears3 on Nov 18, 2019

janeli1

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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mspears3

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Reply 2 on: Nov 18, 2019
Gracias!

irishcancer18

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Reply 3 on: Yesterday
:D TYSM

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