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Author Question: As the average service rate increases, the shape of the negative exponential distribution of service times (Read 86 times)

panfilo

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  • Posts: 572
on: Dec 3, 2019

Question 1

A waiting line model meeting the assumptions of M/M/1 has an arrival rate of 2 per hour and a service rate of 6 per hour; the utilization factor for the system is approximately
◦ 0.33.
◦ 3.00.
◦ 0.25.
◦ 0.50.
◦ 0.67.

Question 2

As the average service rate μ increases, the shape of the negative exponential distribution of service times
◦ takes on a more uniform slope over a wide range of service times.
◦ becomes less gently curved as it moves ever closer to the graph origin.
◦ grows steadily steeper without limit.
◦ changes in appearance from convex to concave.
◦ has an ever steeper slope that eventually turns positive.
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Marked as best answer by panfilo on Dec 3, 2019

moormoney

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Reply #1 on: Dec 3, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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panfilo

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Reply 2 on: Dec 3, 2019
YES! Correct, THANKS for helping me on my review

ultraflyy23

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Reply 3 on: Yesterday
Wow, this really help

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