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Author Question: From a portion of a probability distribution, you read that P(demand = 0) is 0.05, P(demand = 1) is ... (Read 51 times)

arivle123

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Question 1

From a portion of a probability distribution, you read that P(demand = 1) is 0.05, P(demand = 2) is 0.15, and P(demand = 3) is .20. The cumulative probability for demand 3 would be
◦ 0.133.
◦ 0.400.
◦ 0.200.
◦ 0.600.
◦ cannot be determined from the information given.

Question 2

From a portion of a probability distribution, you read that P(demand = 0) is 0.05, P(demand = 1) is 0.10, and P(demand = 2) is 0.20. The two-digit random number intervals for this distribution beginning with 01 are
◦ 01 through 05, 06 through 15, and 16 through 35.
◦ 01 through 05, 01 through 10, and 01 through 20.
◦ 01 through 06, 07 through 16, and 17 through 36.
◦ 00 through 04, 05 through 14, and 15 through 34.
◦ 00 through 04, 00 through 09, and 00 through 19.


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Marked as best answer by arivle123 on Dec 3, 2019

shewald78

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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arivle123

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Reply 2 on: Dec 3, 2019
Thanks for the timely response, appreciate it


jamesnevil303

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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