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Author Question: A television station claims that the amount of advertising per hour of broadcast time has an average ... (Read 51 times)

dakota nelson

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A television station claims that the amount of advertising per hour of broadcast time has an average of 12 minutes and a standard deviation equal to 1.7 minutes. You watch the station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 19 minutes. Calculate the z-score for this amount of advertising time.
◦ z = -4.12
◦ z = -1.44
◦ z = 4.12
◦ z = 1.44


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Marked as best answer by dakota nelson on Jan 16, 2020

meltdown117

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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dakota nelson

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Reply 2 on: Jan 16, 2020
Gracias!


mcarey591

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Reply 3 on: Yesterday
:D TYSM

 

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