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Author Question: A researcher wishes to test H0: 1 = 2 = 3 against H1:at least one of the means is different. Based ... (Read 53 times)

mikaylakyoung

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A researcher wishes to test H0: μ1 = μ2 = μ3 against H1:at least one of the means is different. Based on the ANOVA table, the null hypothesis is rejected and the following output represents the results of Tukey's test. What should the researcher conclude?

Tukey Simultaneous Tests
Response Variable Response
All Pairwise Comparisons among Levels of Treatment
Treatment = 1 subtracted from:
Treatment    Difference            SE of            T- Value      Adjusted
                        of Means        Difference                               P-Value
2                       7.1887              1.982                 3.627              0.0165
3                       0.7488              1.982                 0.3778            0.9251    

Treatment = 2 subtracted from:
Treatment    Difference            SE of            T- Value      Adjusted
                        of Means        Difference                               P-Value
3                      -6.4393               1.982               -3.2489         0.0282

 
 
 


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Marked as best answer by mikaylakyoung on Jan 16, 2020

Madisongo23

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mikaylakyoung

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Reply 2 on: Jan 16, 2020
Excellent


bulacsom

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Reply 3 on: Yesterday
Wow, this really help

 

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