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Author Question: A farmer has five different fields. He wishes to test two different fertilizers. The yields of corn ... (Read 93 times)

Bernana

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on: Jan 16, 2020
A farmer has five different fields. He wishes to test two different fertilizers. The yields of corn may vary from field to field depending on a number of factors such as soil quality, sunlight etc. He divides each field into three sections. For each field, he randomly assigns one of the sections to receive fertilizer A, one of the sections to receive fertilizer B, and one of the sections to receive no fertilizer. At harvest time, he records the corn yields in bushels per acre for each section of each field. The results are shown in the table. Let μ1 be the mean for fertilizer A, μ2 the mean for fertilizer B, and μ3 the mean for no fertilizer. In a test of H0: μ1 = μ2 = μ3 versus H1: at least one of the means is different, the null hypothesis is rejected at the α = 0.05 level of significance. Use Tukey's test to determine which pairwise means differ using a familywise error rate of α = 0.05. Give the P-value for each of the pairwise tests and state your conclusion.
Statistics: Informed Decisions Using Data ¦ Sullivan ¦ 5th Edition
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Marked as best answer by Bernana on Jan 16, 2020

bookworm410

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Reply #1 on: Jan 16, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Bernana

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Reply 2 on: Jan 16, 2020
Excellent

anyusername12131

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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