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Author Question: Solve the problem.Among a random sample of 400 college students, the mean number of hours worked per ... (Read 254 times)

cagreen833

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on: Jan 18, 2020

Question 1

Solve the problem.

Among a random  sample of 250  college students, the mean number of hours worked per week at non-college related jobs is 14.2. This mean lies 2 standard deviation(s) above the mean of the sampling distribution. If a second sample of 250 students is selected, what is the probability that for the second sample, the mean number of hours worked will be greater than 14.2?
◦ 0.0222
◦ 0.9772
◦ 0.5
◦ 0.0228

Question 2

Solve the problem.

Among a random  sample of 400  college students, the mean number of hours worked per week at non-college related jobs is 14.4. This mean lies 2.8 standard deviation(s) above the mean of the sampling distribution. If a second sample of 400 students is selected, what is the probability that for the second sample, the mean number of hours worked will be less than 14.4?
◦ 0.0026
◦ 0.9965
◦ 0.5
◦ 0.9974
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Marked as best answer by cagreen833 on Jan 18, 2020

taylorsonier

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Reply #1 on: Jan 18, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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cagreen833

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Reply 2 on: Jan 18, 2020
Excellent

emsimon14

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Reply 3 on: Yesterday
:D TYSM

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